Question

A body of mass 10kg is moving with a unifrom velocity 100 m/sec is stopped after 10sec.Find the force and distance by it.​

Answer 1

Explanation:

given:

mass of body(m)= 10kg

intial velocity (u) = 100m/sec

final velocity (v) = 0m/s { stop condition}

time (t) = 10sec

calculation

acceleration(f)

acceleration(f) = { (final velocity -intial velocity)/time}

{ (final velocity -intial velocity)/time} ={(0-100)/10}

{ (final velocity -intial velocity)/time} ={(0-100)/10} = -10m/s²

force' = mass(m) × acceleration(f)

=10×(-10)

= -100 kg m/s²

= 100 N ( force' value can not negetive)

distance(s)= ut + 1/2 ft²

= 100 × 10 + 1/2 (-10) 10²

= 1000-500

= 500 m

Answer 2

Answer:

force 100 N, distance 500m.