Question

a body of mass 10kg is moving with a velocity of 1 ms. find: 1. the magnitude of the force required to stop the body in 10s .... 2. the distance the body will move through before coming to rest.

Answer 1

Initial velocity u=1m/s
Final velocity v=0m/s
Time taken t=10s
Acceleration a=(v-u)/t
                       =-0.1m/s^2
Magnitude of acceleration = 0.1
Force F=(mass)*(acceleration)=10*(-0.1)=-1N
Magnitude= 1N
This is the answer for question 1.
Now let us solve question 2 
a=-0.1
v=0
u=1
v²-u²=2as0²-1²=2(-0.1)(s)-1=-0.2s⇒s=5m

Answer 2

Answer:

MAGNITUDE OF FORCE = -1N ( N = Newton )

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