Question

a body of mass 10kg is on a rough horizontal surface.if the coefficient of kinetic friction between the surface in contact is 0.3,the force which can keep it moving with uniform velocity is(take g=9.8m/s2​

Answer 1

Answer:

f= mu R

f = 0.3× mg

= 0.3× 10× 9.8

= 98× 0.3

= 29.4N

Answer 2

GIVEN :

• Mass of the body, m = 10 kg.
• Gravity, g = 9.8 m/s².
• Kinetic friction between the surface in contact is 0.3.

TO FIND :

• The force which can keep it moving with uniform velocity.

FORMULA :

• Force, F = $\mu$mg

SOLUTION :

We know that,

F = $\mu$mg

Here we have m = 10 kg, u = 0.3

F = 0.3 × 10 × 9.8

F = 9.8 × 3

F = 29.4 N

→ $\boxed{F \: = 29.4 \: N}$

•°• The force which can keep it moving with uniform velocity is 29.4 N.