Question

a body of mass 10kg is on a rough horizontal surface.if the coefficient of kinetic friction between the surface in contact is 0.3,the force which can keep it moving with uniform velocity is(take g=9.8m/s2​

Answer 1

Answer:

fk=29.4N

Explanation:

mass=10kg

uk=0.3

g=9.8

fk=ukN(N=mg)

fk=9.8*0.3*10

fk=29.4

Answer 2

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