Question

A body of mass 10kg is raised from certain depth. By the time it is raised by 10m,if its velocity is 2ms inverse,work done during this time is

Answer 1

Given :-

Mass of the body = 10 kg

Height = 10 m

Velocity = 2 m/s

To Find :-

The work done during the time.

Solution :-

We know that,

• m = Mass
• g = Acceleration due to gravity
• h = Height
• v = Velocity
• w = Work

Using the formula,

$\underline{\boxed{\sf Work \ done=mgh+ \bigg( \dfrac{1}{2\ } \ mv^2 \bigg)}}$

Given that,

Mass (m) = 10 kg

Height (h) = 10 m

Velocity (v) = 2 m/s

Substituting their values,

w = 10 × 9.8 × 10 + (1/2×10×2²)

w = 10 × 9.8 × 10 + (1/2×10×4)

w = 980 + (1/2×40)

w = 980 + 20

w = 1000 J

Therefore, the work done during this time is 1000 J.