A body of mass 10kg is raised from certain depth. By the time it is raised by 10m,if its velocity is 2ms inverse,work done during this time is
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4
Answer:
Given that,
Mass of body m=10kg
Height from depth h=10m
Velocity v=2m/s
Now,
Work done = work done to change in P.E + work done in providing K.E to body
W=mgh+21mv2
W=10×9.8×10+21×10×2×2
W=980+20
W=1000J
Hence, the work done is 1000 J
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Answer:
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