a body of mass 10kg is raised from certain depth. by the time it is raised by 10m.if velocity is 2m/s.calculate the work during this time
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Answered by
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W=mgh=10*10*10=1000J
aksht1:
100000j
hi
hlw
where are you from
bahadurgarh
Answered by
5
we have
m=10kg,v=2m/s, h=10
total work = potential energy + kinetic energy.
W=mgh+(1/2mv²)
W=10×9.8×10+(1/2×10×4)
W=980+20
W=1000J
i hope it works.
m=10kg,v=2m/s, h=10
total work = potential energy + kinetic energy.
W=mgh+(1/2mv²)
W=10×9.8×10+(1/2×10×4)
W=980+20
W=1000J
i hope it works.
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