Question

a body of mass 10kg lies on the horizontal surface A horizontal force of 150N produces an acceleration of 10ms in the body find the value of coffeicent of friction​

Answer 1

Answer:

0.8

Explanation:

Let the coefficient of friction be μ.

Normal Force, N=mg

Therefore frictional force f=μmg

When force is F:

Acceleration a=mF−f 

⇒5m=F−f

When force is 2F:

Acceleration a=m2F−f 

⇒18m=2F−f

Comparing both equations and eliminating F:

10m=2F−2f18m=2F−f⇒8m=f=μmg⇒8=μg⇒μ=8/10=0.8