Question

A body of mass 10kg moves according to the relation x=t^2+2t^3.the workdone by the force in the first 2sec is

Answer 1

• Given

=> Mass = 10 kg

=> time = 2 sec

=> displacement = t^2+2t^3

• To Find

=> Force at t = 2 sec ??

• Concept

=> Force = mass × acceleration = m × a

=> acceleration = d^2x/dt^2

• Calculation

=> a = d^2(t^2+2t^3)/dt^2 = 12t + 2

at t = 2 sec ..... a = (12*2) + 2 = 26m/s^2

=> Force = ma = 10×26 = 260 N

• Answer

Force = 260N

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Answer 2

. this is the answer for the question