A body of mass 10kg projected vertically up with 20m/s velocity what will be its PE when its velocity is half of its initial value?
Answers
Answered by
0
Answer:
1500 J
Explanation:
initial velocity= 20m/s
Final velocity= 10 m/s
m= 10 kg
As we know,
P.E= mgh
therefore we need to find h.
Using equation of motion,
V2 - U2 = -2gh
we get,
h = 15 m
Plugging in the value of h,
P.E = 10 X 10 X 15
= 1500J
I hope you understand.....
Answered by
0
Answer:
500J
Explanation:
Loss in kinetic energy = Gain in p.e
final v = 10 m/s
loss in k.e = 1/2*mv^2 = 1/2*10*(20-10)^2 = 500J
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