A' body of mass 10kg slides down an inclined plane from rest. Its height from the ground level is 10m. The inclined plane is not smooth. When the body reaches the ground its speed is 14.m/s. Then how much work is done against friction? (g=10 m/s2) A. 980J B. 1000J C. 20J D. 100J
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i think it Will be B. 1000J
bécause w on inclined plane =Fs cos thita
=> mgh
=10*10*10 =1000J
bécause w on inclined plane =Fs cos thita
=> mgh
=10*10*10 =1000J
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