Question

a body of mass 10kg sliding over a smooth inclined plane of angle 30° and length 0.5m . find the work done by gravitational force​

Answer 1

Answer:

Work = Force × displacement

•sliding force by gravity in the attachment:

•$\bold{{F}_{mg}}$ = mgsin@

•$\bold{{F}_{mg}}$ = 10×10× $\frac {1}{2}$

•$\bold{{F}_{mg}}$ = 50 N

displacement = length = 0.5 m

W = 50 × 0.5

= 25 J

#work done by gravitational force is 25 joules.

hope it helps!