Question

a body of mass 10kg starts from rest and rolls down an inclined plane it rolls down 10m in 2s. What is its velocity at 2s

Answer 1

I am not sure about  the mass. But I have solved with the usage of the mass:

m= 10kg, u=0, S=10m, t=2s

S= ut + 1/2at²

10 = 0 × 2 + 1/2×a×4

10 = 2a

a = 5 m\s²

v = u +at

v = 0 + 5 ×2

v = 10m\s

Hope it helps you...

Answer 2

hello mate ur question is easy ,

given , m=10kg,
s=10m
t=2s
v=?

initially we have formula
s=ut+1/2at^2====(1)
since
u=0
therfore

s=1/2at^2 =====(1)
it is given that distance is 10m and time is 2s
hence we have
10=1/2×a×2×2= 10=a×2
a=10/5= 5ms^-2

here we have got acceleration then we need to get velocity then we have

v=u+ at, such that u=0
v=at= 5×2=10ms^-1
hence v=10ms^-1

######be brainly########