A body of mass 10kgis dropped from a height of 19.8 m what is the velocity
Answers
Answered by
3
What is the velocity when it reaches the bottom?
Here’s the answer
Use equation of motion: v² = u² + 2as
v = sqrt(2gH)
= sqrt(2 × 9.8 m/s^2 × 19.8 m)
= 19.7 m/s
Mass of body is irrelevant.
Here’s the answer
Use equation of motion: v² = u² + 2as
v = sqrt(2gH)
= sqrt(2 × 9.8 m/s^2 × 19.8 m)
= 19.7 m/s
Mass of body is irrelevant.
Answered by
0
we know that
g=10 m/s^2
u=0 (as it is dropped)
using equations of motion
v^2-u^2=2as
v^2=2as + u^2
v^2=2(10)(19.8) + 0^2
v^2=396
or v=19.89 m/s
with this we can also say that matter irrespective of their mass , always fall with same velocity and both reach the ground at the exact same time(given that you drop both the things from same height :D)
but this phenomenon is not seen in our everyday lives, this is because presence of air, which causes friction!
g=10 m/s^2
u=0 (as it is dropped)
using equations of motion
v^2-u^2=2as
v^2=2as + u^2
v^2=2(10)(19.8) + 0^2
v^2=396
or v=19.89 m/s
with this we can also say that matter irrespective of their mass , always fall with same velocity and both reach the ground at the exact same time(given that you drop both the things from same height :D)
but this phenomenon is not seen in our everyday lives, this is because presence of air, which causes friction!
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