Question

A body of mass 12kg is at the bottom of lake of depth 5m if the work done is raising the body to the water surface is 350j the specific gravity of water is?​

Answer 1

Answer:

Loss of weight in water = weight in air / specific gravity = 5/3

Weight of stone in water = 5-5/3 = 10/3

Force = 10/3 x 9.8 = 98/3

Work done = 4 x 98/3 = 130.666 => 130.7(appx)J

Answer 2

Answer:

The specific gravity of water is 5.8 m/s².

Explanation:

Given that,

Mass = 12 kg

Depth = 5 m

Work done = 350 J

We need to calculate the specific gravity

When the body raise to the height then the work done is converted to the potential energy

$W = mgh$

Where, m = mass of a body

g = gravity

h = depth

Put the value into the formula

$350=12\times g\times5$

$g=\dfrac{350}{12\times5}$

$g=5.8\ m/s^2$

Hence, The specific gravity of water is 5.8 m/s².