A body of mass 15 kg is dropped into the water if the Apparent weight of body is 107 Newton then the applied thrust is
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when a body of mass 15 kg is immersed into the water then it applied force or it's weight acts vertically downwards and equals to let W1= 15g N.
and force by the liquid is applied on it in upward direction due to which there seems a decrease in weight of the object which is given let W2 = 107 N.
hence,
W1 - W2 = 107
mg - m'g = 107
or m'g = mg - 107
= 150 - 107
m'g = 43 N
this is the applied thrust on the object.
and force by the liquid is applied on it in upward direction due to which there seems a decrease in weight of the object which is given let W2 = 107 N.
hence,
W1 - W2 = 107
mg - m'g = 107
or m'g = mg - 107
= 150 - 107
m'g = 43 N
this is the applied thrust on the object.
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