A body of mass 15 Kg is
dropped into the water. If the
apparent weight of the body is
107 N, then the applied thrust
will be
Answers
Answered by
1
Explanation:
Apparent weight = Actual Weight - Buoyant thrust
107 = mass × acceleration due to gravity - Thrust
107 = 15 (9.8) - Buoyant thrust
Buoyant thrust = 147 - 107 = 40N
Therefore, it is your answer .
Answered by
0
Answer:
when a body of mass 15 kg is immersed into the water then it applied force or it's weight acts vertically downwards and equals to let W1= 15g N. and force by the liquid is applied on it in upward direction due to which there seems a decrease in weight of the object which is given let W2 = 107 N
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