Question

A body of mass 15 kg moving with a velocity of
10 m/s is to be stopped by a resistive force in 15
sec, the force will be -​

Answer 1

Answer:

750Nm

Explanation:

We know, work done, W = F × s

Where, F is the force applied and s is the distance travelled by the particle.

Also, W = (F/a) × s × a

(dividing and multiplying by a)

where a is deceleration.

We also know,

and from Newton's Second Law of Motion,

F = ma

where m is the mass of the body.

F/a = m

or, F/a = 15

going back to W = (F/a) × s × a , and putting the values, we get,

W = 15 × 50

= 750 Nm

The answer is 750 Nm.

Answer 2

Explanation:

Given, m=15 kg

u=10 m/s

t=15 secs

v will be zero as it is to be stopped.

F=ma

=m(v-u) /t

= 15 (0-10)/15

= -10 m/s

Therefore,

Force to be applied is -10 m/s.

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