Math, asked by juipathak12, 6 months ago

A body of mass 15kg moving with velocity of 10m/s is to be stopped by a resistive force in 15 seconds, find force​

Answers

Answered by MihranAhmad
1

Answer:

-10N

Step-by-step explanation:

Given,

m=15kg

u=10m/s

t=15s

v=0m/s

v = u+at

v-u = at

v-u/t = a

a = (v-u)/t

a=

0-10/15=

-10/15=

-2/3m/s.sq

F = ma

=15 x (-2/3)

= -30/3

= -10N (Answer is negative because the force is exerted in the opposite direction)

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