Question

A body of mass 160 kg at rest is acted upon by a force of 800 N, the distance travelled by the body in 10s is ……
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Answer 1

Given :

Mass of the body = 160kg

Initial velocity = zero

Force acting on the body = 800N

Time taken = 10s

To find :

The distance travelled by the body.

Solution :

Firstly we have to find accerlation of the body

using second law of motion .i.e.,

The rate of change of linear Momentum of a body with time is proportional to the net external force acting on it.

In order words,

F = ma

where,

• F denotes force
• m denotes Mass
• a denotes accerlation

by substituting all the given values in the formula,

$\leadsto \sf F = ma$

$\leadsto \sf 800 = (160)(a)$

$\leadsto \sf a = \dfrac{800}{160}$

$\leadsto \sf a = 5 \: {ms}^{ - 2}$

Now, using second equation of motion that is,

$\boxed{\bf s = ut + \dfrac{1}{2} {at}^{2} }$

where,

• s denotes distance covered
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

substituting all the given values in the equation,

$\leadsto \sf s = ut + \dfrac{1}{2} {at}^{2}$

$\leadsto \sf s =(0)(10) + \dfrac{1}{2}(5) {(10)}^{2}$

$\leadsto \sf s = \dfrac{1}{2} \times 5 \times 100$

$\leadsto \sf s =250 \: m$

thus, the distance travelled by the body is 250 m.