Question

A body of mass 17kg is initially at rest on a horizontal frictionless surface. A force of 50N acts on it and accelerates to a final speed of 18m/s calculate the distance travelled?

And the work done by the force in kilo joules?

Answer 1

Explanation:

by second law of motion by newton

Force =Mass×Acceleration

50N=17kg×A

A=3m/s² (approx)

time =v-u/a

v=final velocity u=initial velocity

18-0/3=6seconds

distance =ut+1/2at² (second equation of motion)

distance =0×6+1/2×3×6²

=0+1/2×3×36

=54m

work =force×displacement

50×54

2700J or N.m

1000J=1KJ

2700J=2.7KJ

hope you got it

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