Question

A body of mass 1kg and carrying positive charge 0.01C
horizontal. An electric field Eis applied to stop the body.
is sliding down an inclined plane of angle 30° with the
If the coefficient of friction between the body and the
​

Answer 1

Answer:

In equilibrium

N=Eqsin30+mgcos30−−−−−−−(1) and

f+Eqcos30=mgsin30−−−−−−−(2)

Maximum static function is μN

⇒f=μN

μN+Eqcos30=mgsin30−−−−−−−(3)

Solving (1), (2) and (3)

− EEqcos3 /u+ mgsin30/u =Eqsin30+mgcos30

E( qqcos3/y +qsin30)=mg(−cos30+ sin30/u)

$$E\times (0\cdot 01)(\dfrac {\sqrt 3\times 2\sqrt 3}{2}+\dfrac {1}{2})=1\times

10(\dfrac {-\sqrt 3}{2}+\dfrac {1}{2}2\sqrt 3)$$

E×0⋅01×5 2/7 10×( √3/2)

E= 10√30/0.01×7

= 1000√3/7