a body of mass 1kg crosses a point O with velocity 60m/s. A force of 10N directed towards O acts on it. In how much time will it again cross O?
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Answered by
5
F = ma
F = mv/t(a=v/t)
10 = 1 x 60/t
t = 60/10
t = 6 sec
F = mv/t(a=v/t)
10 = 1 x 60/t
t = 60/10
t = 6 sec
Answered by
0
Hey
It will never pass the point O again because the force is going in the direction of velocity so velocity never decrease also the acceleration is also positive.
Hope it helps :)
It will never pass the point O again because the force is going in the direction of velocity so velocity never decrease also the acceleration is also positive.
Hope it helps :)
subhishaa:
the force is acting in the opposite direction
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