Question

a body of mass 1kg drops from the top of towr of height 50m what will be its K.E 10m below the top

Answer 1

GiveN :-

• A body of mass 1kg drops from the top of tower of height 50m .

To FinD :-

• The K.E 10m below the top .

SolutioN :-

Given that a body of mass 1kg is dropped from a tower of height 50m . We need to find the the kinetic energy 10m below the top. So ,

$\red{\frak{ Given }}\begin{cases} \textsf{ Mass of the body =\textbf{ 1 kg } . } \\\textsf{ Height of the tower =\textbf{ 50 m } . }\end{cases}$

We will have to find its velocity at 10m below from the top . Which can be calculated from the formula $\bf v_{( At\ h )}=\sqrt{ 2gh }$ which is applicable under free fall .

★ Using the formula of Kinetic Energy:-

$\sf:\implies\pink{ K.E . =\dfrac{1}{2} mv^2}\\\\\sf:\implies K.E. =\dfrac{1}{2}\times (1kg)^2 \times (\sqrt{2gh })^2 \\\\\sf:\implies K.E. =\dfrac{1}{2} \times 1 \times 2\times 10 \times 10 \\\\\sf:\implies \underset{\blue{\bf Required\ Energy}}{\underbrace{\boxed{\pink{\frak{ K.E. = 100 \ Joules }}}}}$