Question

A body of mass 1kg is acted upon by two force each of magnitude 1N making angle 60 degrees with each other. find net acceleration of body

Answer 1

A= F1 = 1 N

B= F2 = 1 N

θ = angle between the 2 forces = 60°

Cos(60) = 1/2

Now Resultant force = √[A^2 + B^2 + 2A.B.Cos(θ)]

                                =√ (A^2 + B^2) = √3 N

F = √3 N

m = 1 kg

a = F /m = (√3)/1 m/s^2 = √3 m/s^2

Answer 2

Answer:

Explanation:

m=1kg

we have 2 forces 1n each making an angle of 60degrees

by using parallelogram law of vector addition

Fnet=√f1² + f2² + 2×f1×f1×cosθ

√1²+1²+2×1×1×1/2

= √3

F=ma

a=F/m

a=√3/1

a=√3