Question

a body of mass 1kg is at rest on a frictionless surface.what is the distance travelled by it in 20 s when acted upon by a force of 10 -2 N?
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Answer 1

Answer: 1600 m

Explanation:

m (Mass) = 1 kg

t (Time) = 20 s

F (Net force) = 10 N - 2N = 8N

u (initial velocity) = 0 m/s

F = ma => a = F/m = 8/1 = 8 m/s²

So, s = ut + $\frac{1}{2}$at²

=> s = (0 × 20) + ($\frac{1}{2}$ × 8 × 20 × 20)

=> s = 4 × 400 = 1600 m

∴ The body will travel a distance of 1600 m or 1.6 km.

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