Physics, asked by princemahesh0268, 5 months ago

A body of mass 1kg is dropped from a height of 5m on to the ground.If the body prnetrates 2cm in to the ground, the average resistance offered by the ground on to the body is (g=10m/sec)​

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Answered by Anonymous
24

Explanation:

your answer

A body of mass 1kg is dropped from a height of 5m on to the ground.If the body prnetrates 2cm in to the ground, the average resistance offered by the ground on to the body is (g=10m/sec)

(g=10m/sec)

body of mass 1 kg is dropped from a height of 5 m on to the ground. If the body penetrates 2 cm in to the ground, the average resistance offered by the ground on to the body is (g=10ms

−2

)

YOUR ANSWER..... 2510 N.

Mass of body = 1 kg

body droped from night= 5cm

body pratent one gram on to ground = 2 cm

velocity at ground √ 2 gh

= 2 × 10 × 5

V=. 10 m/ s

FINAL ANSWER= 2510N ( Newton)

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