Question

a body of mass 1kg is kept at rest a constant force of 6 Newton start acting on it find the time taken by a body to move through a distance of 12 m

Answer 1

m= 1kg

s= 12m

u= 0 m/s

F= 6N

F=m*a

6=1*a

a=6 m/s^2

v^2=u^2+2a*s

v^2=0+2*6*12

v^2=144

v= 12

=> v=u+at

=> 12=0+6*t

=> t= 12/6

t= 2 sec

so the answer is 2 second

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Answer 2

acceleration = force /mass = 6/1 = 6 m/s^2
s = ut + (1/2)at^2
u =0
so, 12 = (1/2)6t^2
t= 2 seconds