Question

A body of mass 1kg is kept at rest .A constant force of 6 newton starts acting on it . find the Time taken by the body to move through a distance of 12m

Answer 1

acc. = 6/1 = 6 m/sec^2

s = 12 = 1/2 at^2

12 = 1/2 * 6 * t^2

4 = t^2

t = 2 sec

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Answer 2

Hola mate !! ✨✨

here's your answer...⬇️⬇️

$f = m \times a$

$a = f \div m \\ \\ a = 6 \div 1 \\ \\ a = 6 \: m {s}^{ - 2}$

◾according to second equation of motion ,

$s = ut \: + \: \frac{1}{2}a {t}^{2} \\ \\ s = \frac{1}{2}a {t}^{2} \\ \\ {t}^{2} = \: \frac{2s}{a} = \frac{24}{6} \\ \\ {t }^{2} = 4 \\ \\ t \: = 2 \: sec$

$\boxed{\large{\blue{hope\: it\: helps\: !!}}}$ ❣️❣️