Physics, asked by HarshavardhanGV, 2 days ago

A body of mass 1kg is moving with 15m/s is stopped in 2sec . Calculate the impulse and opposing force.​

Answers

Answered by ImperialGladiator
22

Answer:

  • Opposing force = -7.5
  • Impulse = 15 N

Explanation:

Given, A body of mass 1kg moving with a velocity of 15m/s comes at rest 2 seconds.

Calculate,

  • Impulse.
  • Opposing force.

Here,

the body comes to rest so final velocity (v) would be zero

Acceleration of the body,

→ a = (v - u)/t

Where,

  • v denotes the final velocity
  • u is the initial velocity = 15 m/s.
  • t is the time = 2 sec

→ a = (0 - 15)/2

→ a = -15/2

→ a = -7.5

[Note: -ve sign denotes the against motion.]

Opposing force is given by,

→ F = m*a

Where,

  • m is the mass of the body
  • And, a is the acceleration.

→ F = 1*(-7.5)

→ F = -7.5

[Note: -ve sign denotes the opposite force.]

Now, Impulse of the body is given by,

Where,

  • F is the force.
  • t is time taken.

→ I = 7.5*2

→ I = 15.0

Impulse of the body is 15 N

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Answered by StarFighter
32

Answer:

Given :-

  • A body of mass 1 kg is moving with 15 m/s is stopped in 2 seconds.

To Find :-

  • What is the impulse and opposite force.

Formula Used :-

\clubsuit First Equation Of Motion Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{v =\: u + at}}}\: \: \: \bigstar\\

where,

  • v = Final Velocity
  • u = Initial Velocity
  • a = Acceleration
  • t = Time Taken

\clubsuit Force Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{F =\: m \times a}}}\: \: \: \bigstar\\

where,

  • F = Force
  • m = Mass
  • a = Acceleration

\clubsuit Impulse Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{Impulse =\: Force \times Time}}}\: \: \: \bigstar\\

Solution :-

First, we have to find the acceleration :

Given :

  • Final Velocity (v) = 0 m/s
  • Initial Velocity (u) = 15 m/s
  • Time Taken (t) = 2 seconds

According to the question by using the formula we get,

\implies \bf v =\: u + at

\implies \sf 0 =\: 15 + a(2)

\implies \sf 0 =\: 15 + 2a

\implies \sf 0 - 15 =\: 2a

\implies \sf - 15 =\: 2a

\implies \sf \dfrac{- 15}{2} =\: a

\implies \sf - 7.5 =\: a

\implies \sf\bold{\blue{a =\: - 7.5\: m/s^2}}\\

Hence, the acceleration is - 7.5 m/ .

Now, we have to find the opposite force of a body :

Given :

  • Mass (m) = 1 kg
  • Acceleration (a) = - 7.5 m/

According to the question by using the formula we get,

\implies \bf F =\: m \times a

\implies \sf Force =\: Mass \times Acceleration\\

\implies \sf Force =\: 1 \times (- 7.5)

\implies \sf\bold{\purple{Force =\: - 7.5\: N}}\\

Hence, the opposite force of a body is - 7.5 N .

Now, we have to find the impulse :

Given :

  • Force = 7.5 N
  • Time = 2 seconds

According to the question by using the formula we get,

\dashrightarrow \bf Impulse =\: Force \times Time\\

\dashrightarrow \sf Impulse =\: 7.5\: N \times 2\: s\\

\dashrightarrow \sf\bold{\red{Impulse =\: 15\: N\: s}}\\

\therefore The opposite force of a body is - 7.5 N and the impulse is 15 N s .

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