Question

A body of mass 1kg is moving with velocity 30 m/s due north . It is acted on by a force of 10 N due west for 4 seconds. Find the velocity of the body after the force ceases to act.​

Answer 1

Along North

Velocity after 4s

v_x = 30 m/s

Along West

Velocity after 4s

v_y = at

= (F/m) × t

= (10/1) × 4

= 40 m/s

Velocity after 4s = sqrt(v_x^2 + v_y^2)

= sqrt(30^2 + 40^2)

= 50 m/s

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