Question

A body of mass 1kg is performing linear sHM its displacement x(cm) at t(second) is given by

X=6sin (100t+π/4) maximum kinetic energy of the body​

Answer 1

Answer:

K. E=(X²-36)×10⁴/2

Explanation:

As we know that a function can be expressed in the form of A sin(omega T +phi )

As we compared this to the question we get

Omega=100

A=6

As we all know that

K. E=Omega² (x²-A²) /2

By substituting we can get

K. E=10⁴ (X²-36)/2

Answer 2

Explanation:

y=Asin(wt+@)

A=6cm

m=1kg

w=100 rad/sec

KEmax=1/2mw^2A^2

=1/2×1×(100)^2×(10^-2)^2×6^2

=18J

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