Question

A body of mass 1kg lies on an inclined plane of angle 60 to the horizantal. If the coefficient of friction is 0.4 the frictional force along the inclined plane is

Answer 1

Hey Mate


Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N


Applied force = F = ma = 1 × 5 = 5 N


As F < f, so force of friction = 5 N


hope this answer helps you
please mark it as brainliest

Answer 2

HIII ......



GOOD MORNING;-)


HERE IS YOUR ANSWER:--------


f= 0.6×1×9.8= 5.88N.
APLLIED FORCE= 1×5=5N


THEREFORE ,5N IS THE ANSWER.



HOPE THIS HELPS YOU


BE ALWAYS HAPPY AND SMILING.......