Question

A body of mass 1kg moves from points A(2m, 3m,4m) to B(3m,2m,5m). During motion of body, a force F= (2N)i-(4N)j acts on it. the work done by the force on the particle during displacement is​

Answer 1

Answer:

Answer is (a)

Explanation:

Position vector of point A is given by-:2i^+3j^+4k^

Position vector of point B is given by-:3i^+2j^+5k^

Hence displacement is B-A=i^-j^+k^=S

F=(2i^-4j^)N

Hence W=F•S=2+4=6J.