A body of mass 1kg moving with 40ms–1 hits a spring of force constant 2800N/m as shown in the figure. The
compression in the spring by the time the speed of the body reduces by one-fourth of initial speed is (ignore friction)
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Answered by
0
Answer:
Given that,
Mass m=0.1kg
Velocity v=10m/s
Force constant k=1000N/m
Now, by using the formula
2
1
mv
2
=
2
1
kx
2
x
2
=
1000
0.1×10×10
x
2
=0.01
x=0.1m
Hence, the compression of the spring is 0.1 m
Explanation:
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Answered by
0
Answer:
Given that,
Mass m=0.1kg
Velocity v=10m/s
Force constant k=1000N/m
Now, by using the formula
2
1
mv
2
=
2
1
kx
2
x
2
=
1000
0.1×10×10
x
2
=0.01
x=0.1m
Hence, the compression of the spring is 0.1 m
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