Physics, asked by gujjavarshith, 1 month ago

A body of mass 1kg moving with 40ms–1 hits a spring of force constant 2800N/m as shown in the figure. The
compression in the spring by the time the speed of the body reduces by one-fourth of initial speed is (ignore friction)

Answers

Answered by nandini9322
0

Answer:

Given that,

Mass m=0.1kg

Velocity v=10m/s

Force constant k=1000N/m

Now, by using the formula

2

1

mv

2

=

2

1

kx

2

x

2

=

1000

0.1×10×10

x

2

=0.01

x=0.1m

Hence, the compression of the spring is 0.1 m

Explanation:

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Answered by manalikaraj2007
0

Answer:

Given that,

Mass m=0.1kg

Velocity v=10m/s

Force constant k=1000N/m

Now, by using the formula

2

1

mv

2

=

2

1

kx

2

x

2

=

1000

0.1×10×10

x

2

=0.01

x=0.1m

Hence, the compression of the spring is 0.1 m

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