Question

A body of mass 1kg tied to one end of string is revolved in a horizontal circle of radius 0.1 m with a speed of 3 revolution /sec , assuming the effect of gravity is negligible , then linear velocity , acceleration and tension in the string will be

1. 1.88m/s, 35.5m/^2 , 35.5N
2.2.88m/s, 45.5m/s^2, 45.5N
3.3.88m/s, 55.5m/s^2, 55.5N
4.None of these

Answer 1

option 1.......linear velocity will be 0.6*pi=1.88m/s....as angular velocity 6*pi rad/sec...multiply with radius to get that...linear acceleration is 35.5 m/s^2 as angular acceleration is ( linear velocity^2/radius)....and multiply it with radius again to get linear acceleration... as 3.6*(pi)^2=35.5......and tension is (m(v^2)/r) ie centrifugal force ...=35.5N..

Answer 2

Answer:

option 1

step by step explanation

• omega=theta/time
• omega=2π*3/1
• omega=6π
• velocity=omega*radius
• velocity=6π*0.1
• velocity= 1.88m/s

• acceleration=omega^2*radius
• acceleration=36π^2*0.1
• acceleration=35.5m/s^2

• Tension=mass*velocity^2/radius
• tension=1*1.88*1.88/0.1
• Tension=35.5N

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