A body of mass 2.00 kg and density kg/m3 is completely dipped in a liquid of density 800kg/m3. Find the force of buoyancy on it
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ρ1 = 8000 kg/m^3
ρ2 = 800 kg/m^3
M = 2 kg
g = 9.8 m /s^2
Volume of the cube V = M/ρ1 = 2 / 8000 = 0.25 x 10^-3 m^3
Buoyancy is the upward force on the cube which is equal to the weight of the volume of the liquid displaced by it.
B = mg = ρ2 V g = 800 x 0.25 x10^-3 x 9.8 = 1.96 N
ρ2 = 800 kg/m^3
M = 2 kg
g = 9.8 m /s^2
Volume of the cube V = M/ρ1 = 2 / 8000 = 0.25 x 10^-3 m^3
Buoyancy is the upward force on the cube which is equal to the weight of the volume of the liquid displaced by it.
B = mg = ρ2 V g = 800 x 0.25 x10^-3 x 9.8 = 1.96 N
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