Physics, asked by Satvik1476, 10 months ago

A body of mass 2.5 kg takes 5 seconds to stop when a force 10 N is applied in a direction opposite
to the motion of the body. The initial speed of the body was:
(A) 20 m/s
(B) 10 m/s
(C) 15 m/s
(D) 25 m/s​

Answers

Answered by Anonymous
10

Answer:-

Given:-

  • Mass of the body (m) = 2.5 kg
  • Time taken to stop (t) = 5 s
  • Force applied on it (F) = - 10 N (Force acted on the opposite side)
  • Final velocity (v) = 0 m/s

To Find:-

Initial velocity (u) in the case.

___________...

We know,

F = ma

F = m[(v - u)/t]

F = m(-u/t)

(Since, v = 0)

where,

  • F = Force,
  • m = Mass,
  • a = Acceleration,
  • v = Final velocity &
  • u = Initial velocity.

Let the initial velocity in this case be = u

∴ (2.5 kg) (- u/5s) = - 10 N

➵ 25/10 kg × -u/5s = - 10 kg m/s²

➵ (-25 u)/(50) kg s^-1 = - 10 kg m/s²

➵ - ½ u kg s^-1 = - 10 kg m/s²

➵ ½ u kg/s = 10 kg m/s²

➵ ½ u = (10 kg m/s²)/(kg) × s

➵ ½ u = 10 m/s

➵ u = 10 × 2 m/s

➵ u = 20 m/s

(A) 20 m/s

Answered by bhakti34
2

Answer:

answer is 10 m/s.....

you can trust me

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