Question

A body of mass 2.5kg is acted by two perpendicular forces 3N and 4N calculate the magnitude and direction of acceleration of the body

Answer 1

Let 2 forces be f1 and f2

f1=3. f2 =4

Angle b/w them is 90

So their resultant =

3N²+ 4N²=R²

25= R²

R=5N

As F=ma

A=F/m

a=5/2.5

a= 2m/s²

Hope this may help u