Question

A body of mass 2 g is executing SHM about a mean position with an amplitude 10 cm. If the maximum velocity is 100 cm s^-1 its velocity is 50 cm s^-1 at a distance of (in cm).

Answer 1

Velocity of the particle in SHM, v = ω√(A2 – y2)
where y is displacement..
and Vmax=A(omga)==>omga=100/10=10

now   v = ω√(A2 – y2)=>50=sqrt(10^2-y^2)
taking squre on both sides we have 2500=100(10- y)
2500/100=10- y==>y=25-10

hence y=15cm