Question

A body of mass 2 kg at rest applied by a constant force 20 N for 2 sec calculate the distance covered​

Answer 1

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Answer 2

Answer:

Given : F=10 N m=2 kg t=2 s u=0 m/s

Acceleration of the body a = F/m = 10/2 = 5m/s^2

Distance covered = S = ut + 1/2 at^2

= 0 × 2 + 1/2 × 5 × 2^2

= 0 + 1/2 × 5 × 2 × 2

= 10m

Distance covered by the body in 2sec = 10m