Question

a body of mass 2 kg at rest is applied with force 8 N what is kinetic energy of the body at end of 12 sec
​

Answer 1

Answer:

2*12

,

-14 is energy of the motion

Answer 2

Question :

A body of mass 2kg at rest is applied with force 8N what is kinetic energy of the body at the end of 12 sec.

To find :

Kinetic energy (KE)=?

Given :

•mass = 2kg

• force=8N

• Time=12sec

Formula :

$\red\bigstar\large\boxed{\sf{Kinetic \: energy =\dfrac{1}{2}mv^2}}$

Solution :

$\implies\large\sf{Force=mass \times acceleration }$

$\implies\large\sf{ 8N=2kg \times acceleration }$

$\implies\large\sf{accleration= 4 m/s^2}$

$\implies\boxed{\large\sf{acceleration=4m/s^2}}$

$\bf{by \: using \: Newton's \: first \: law}$

$\implies\large\sf{v=u+at}$

$\implies\large\sf{v=0+(4)(12)}$

$\implies\large\boxed{\sf{velocity=48m/s}}$

$\implies\large\sf{KE=\dfrac{1}{2}mv^2}$

$\implies\large\sf{KE=\dfrac{1}{2} \times 2 \times (48)^2}$

$\implies\large\sf{KE= 48 \times 48 =2,304}$