Question

a body of mass 2 kg changes its velocity from 10 ms-^ 1 to 20 MS -^1 in 5 seconds find the magnitude of the force applied​

Answer 1

Answer:

4 N

Explanation:

Mass = 2 kg

Acceleration = 20-10/5= 2 ms^-2

Force = Mass * Acceleration

=2* 2 N =4N

Answer 2

Given :

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 20 m/s
• Time (t) = 5 seconds
• Mass (m) = 2 kg

To find :

• Force applied

According to the question,

At first we have to find acceleration then we will find force

$\star \boxed{ \sf \blue{v = u + at}}$

$\sf{ \implies20 = 10 + a \times 5}$

$\sf \implies{20 - 10 = 5a}$

$\sf \implies{10 = 5a}$

$\implies \sf{a = \cancel\frac{10}{5} {}^{ \: \: \:2} }$

$\sf \implies a = 2 \: {ms}^{2} \green \bigstar$

Now we will calculate the force

$\star \boxed{ \sf \blue{F= ma}}$

$\sf{ \implies 2\times 2}$

$\sf{ \implies 4\:N}\green\bigstar$

So,the force is 4 N...