Question

A body of mass 2 kg collides with a wall with speed 100 m/s and rebounds with
the same speed. If the time of contact was 1/50 second, the force exerted on the
wall is:
8N
2 x 104 N
4N
104 N​

Answer 1

Answer:

option 2

Step-by-step explanation:

change in momentum=mv-(mu)=mu-(-mu)=2mu

=2×2×100=400

F=dP/dt=400×50=20000 N=2×10⁴ N

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