A body of mass 2 kg collides with another bosy at rest with mass m find m
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Answer:
By conservation of linear momentum
2v
0
=2(
4
v
0
)+mv⇒2v
0
=
2
v
0
+mv⇒
2
3v
0
=mv....(1)
since collision is elastic
v
separation
=v
apprach
⇒v−
4
v
0
=v
0
⇒
4
5v
0
=v....(2)
equating (2) and (1)
4
3v
0
=m(
4
5v
0
)⇒m=
5
6
=1.2kg
solution
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