Question

A body of mass 2 kg fall from rest what will be its kinetic energy during the fall after 2 sec . Assume g=10m/S2

Answer 1

v = u +at

v = 0+gt

v=10*2 = 20 m/s

K.E. = (1/2)mv2 = 0.5*2*400 = 400 joule