Question

A body of mass 2 kg fall vertically, passing through
two points A and B. The speeds of the body as it
passes A and B are 1 m/s and 4m/s respectively.
The resistance against which the body falls is 9.6N.
What is the distance AB?
(A) 2m
(B) 3m
(C) 6m
(D) 1.5 m​

Answer 1

The distance between A and B is 1.5 m

D is correct

Explanation:

A body of mass 2 kg fall vertically, passing through  two points A and B.

Speed of body at point A, u = 1 m/s

Speed of body at point B, v = 4 m/s

The resistance against which the body falls is 9.6 N

Let d be distance between point A and point B

Using work energy theorem

$W=\Delta KE$

where, W = Fd and $KE=\dfrac{1}{2}mv^2$

$9.6d = \dfrac{1}{2}\times 2(4^2-1^2)$

$9.6d = 15$

$d=1.5$

Hence, the distance between A and B is 1.5 m

Learn more:

work energy theorem

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Answer 2

Answer:

answer D is correct

Explanation:

i hope u helped from this