Math, asked by nikithacs2335, 4 days ago

A body of mass 2 kg falls from rest and has a kinetic energy of 2000 J just before it touches the ground. Neglecting friction, calculate a) the loss in Ep during the fall. b) the height from which the body has fallen.

Answers

Answered by satyamdantare1to3
0

Step-by-step explanation:

PLS MARK AS BRAINLIEST.

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Answered by Acer27
0

Answer: (a) 2000 J , (b) 100 meters

Step-by-step explanation:

Given :-

Mass of body = 2 kg

Acceleration due to gravity = 10 m/s²

Kinetic Energy just before touching the ground (Max. KE) = 2000 J

We know from the Law of Conservation of Energy, that during a free-fall motion (neglecting air friction/drag), the loss in Potential Energy = the gain in Kinetic energy.

We also know that the Kinetic Energy of the object just before touching the ground is maximum, or in other words, the Potential Energy of the object is minimum.

The object had the gain of 2000 J in its Kinetic Energy, hence the loss in its Potential Energy will be 2000 J. (a)

Now, it is given that its maximum Kinetic Energy of the object was 2000 J.

Formula :- Kinetic Energy = 1/2·m·v²

We have the mass of the body as 2 kg.

1/2 × 2 × v² = 2000 J

→ v² = 2000

⇒ v = √2000 m/s

We know that the object fell from rest, and from the equation of motion,

v² + u² = 2as

→ 2000 = 2( 10 ) × s

→ s = 2000/20

s = 100 m

So the object fell from a height of 100 meters. (b)

Note :- All these measurements are taken into consideration keeping in mind, the acceleration due to gravity as 10 m/s².

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