Question

A body of mass 2 kg has an initial velocity of 3 m/s along oe and it is subjected to a force of 4 n in a direction perpendicular to oe. the distance of body from o after 4 second will be

Answer 1

$m = 2kg \\ u = 3 \\ f = 4 \\ t = 4 \\ f = ma \cos{x}\\ f = 2a \cos{90}\\ f = 0$
Since the net force on the body is 0 due to the direction the force is applied in, the body will be at a distance of 0 metres from the original position.
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