Question

a body of mass 2 kg has an initial velocity of 3 metre per second along OE and it is subjected to a force of 4 n in a direction perpendicular to OE. the distance of body from after 4 second will be​

Answer 1

Answer:

The distance of the after 4 second will be 28 meter

Answer 2

Explanation:

Let OE and OY be along X and Y axis respectively,

then u

x

=3m/s,a

x

=0

and u

y

=0,a

y

=

2

4

=2m/s

2

at t=4s, let S

x

and S

y

be the displacement along x-axis and y-axis respectively, then

S

x

=u

x

=

2

1

a

x

t

2

=3×4+

2

1

(0)(4)

2

=12m

and

S

y

=u

y

t+

2

1

a

y

t

2

=0×4+

2

1

(2)(4)

2

=16m

so, the resultant displacement S is given as

S=

S

x

2

+S

y

2

=20m